알고리즘
[C++] 백준 2941번: 크로아티아 알파벳
mezo
2019. 9. 29. 21:33
728x90
반응형

#include <iostream>
#include <string>
#include <vector>
using namespace std;
int solution(string word) {
int count = 0;
for (int i = 0; i < word.size(); i++) {
if (word[i] == 'c') {
if (word[i + 1] == '=' || word[i + 1] == '-')
i++;
}
else if (word[i] == 'd') {
if (word[i + 1] == 'z'&& word[i + 2] == '=') {
i++;
i++;
}
else if (word[i + 1] == '-')
i++;
}
else if (word[i] == 'l'&&word[i + 1] == 'j')
i++;
else if (word[i] == 'n'&& word[i + 1] == 'j')
i++;
else if (word[i] == 's' && word[i + 1] == '=')
i++;
else if (word[i] == 'z' && word[i + 1] == '=')
i++;
count++;
}
return count;
}
int main(void){
string word;
cin >> word;
int result;
result = solution(word);
cout << result;
return 0;
}
728x90
반응형